Since Pi is infinite and non-repeating, would that mean any finite sequence of non-repeating numbers should appear somewhere in Pi?

@Melatonin@lemmy.dbzer0.com · edit-2 4M

Since Pi is infinite and non-repeating, would that mean any finite sequence of non-repeating numbers should appear somewhere in Pi?

@weker01@sh.itjust.works · 4M

Let me give another counterexample. Let x be the binary expansion of pi i.e. the infinite string representing pi in base 2.

Now you will not find 2 in this sequence by definition but it’s still a non-repeating number.

Now one can validly say that we restricted our alphabet and we should look only for finite strings with digits that actually occure in the number. The answer is the string “23456789” concatenated with x.

Kairos · 4M

That’s like saying your car is busted because it can’t drive on a road made of broken glass.

@weker01@sh.itjust.works · edit-2 4M

That’s mathematics. It do be like that sometimes. Counterexamples can be stupid but still valid.

It’s on you to prove your claims.